x^2+90x-486000=0

Solution for x^2+90x-486000=0 equation:

x^2+90x-486000=0

a = 1; b = 90; c = -486000;
Δ = b2-4ac
Δ = 902-4·1·(-486000)
Δ = 1952100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1952100}=\sqrt{8100*241}=\sqrt{8100}*\sqrt{241}=90\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90\sqrt{241}}{2*1}=\frac{-90-90\sqrt{241}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90\sqrt{241}}{2*1}=\frac{-90+90\sqrt{241}}{2}
$